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For x2−6x+5=0x^2 - 6x + 5 = 0, using x=−b±b2−4ac2ax=\frac{-b\pm\sqrt{b^2-4ac}}{2a}, the value of −b-b is _____

Use standard form ax2+bx+c=0ax^2+bx+c=0 and substitute carefully.

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Updated 2026-09-20

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