An industrial safety model for materials released from an elevated platform uses the function $h(t) = -16t^2 + 64t + 80$ to determine height $h$ (in feet) after $t$ seconds. Based on the analysis of this model, after how many seconds does a released object hit the ground level ($h(t) = 0$)?

A workplace safety officer is using the height model $h(t) = -16t^2 + 64t + 80$ to monitor the trajectory of a component released from an elevated platform. Arrange the following events in the chronological order in which they occur, from the moment of release until the object impacts the ground.

A safety supervisor is using the trajectory model $h(t) = -16t^2 + 64t + 80$ to monitor the path of a component released from an elevated platform. Match each specific time $t$ (in seconds) with the corresponding height or physical event described by the model.

In the industrial trajectory model $h(t) = -16t^2 + 64t + 80$, the mathematical solution $t = -1$ is discarded because time cannot be negative in a physical workplace scenario.

A safety engineer is calculating the impact time of falling debris using the trajectory model $h(t) = -16t^2 + 64t + 80$. Upon factoring the equation to find when the debris hits the ground, they obtain the mathematical solutions $t = 5$ and $t = -1$. The solution $t = -1$ must be discarded because elapsed time cannot be ____ in this physical workplace scenario.