Write $48{,}300$ and $0.0129$ in scientific notation by applying the conversion steps.

Part ⓐ — Write $48{,}300$ in scientific notation.

1. Move the decimal point: Shift the implied decimal point to the left to obtain a number between $1$ and $10$. This results in $4.83$.
2. Count the places moved: The decimal point was moved 4 places to the left.
3. Write as a product with a power of $10$: Because the original number is greater than $1$, the exponent is positive $4$. The result is $4.83 imes 10^4$.

Part ⓑ — Write $0.0129$ in scientific notation.

1. Move the decimal point: Shift the decimal point to the right to get $1.29$.
2. Count the places moved: The decimal point was moved 2 places to the right.
3. Write as a product with a power of $10$: Because the original number is between $0$ and $1$, the exponent is negative $-2$. The result is $1.29 imes 10^{-2}$.

Therefore, $48{,}300 = 4.83 imes 10^4$ and $0.0129 = 1.29 imes 10^{-2}$.