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Case Study

Explain how the researcher should interpret this pp-value of .03.03 relative to their alpha level, detailing the appropriate decision regarding the null hypothesis and what this decision means for the effectiveness of the new study technique.

Case context: A researcher is conducting a study to determine if a new study technique improves test scores compared to standard methods. After running a tt-test on the data, the analysis program outputs a pp-value of .03.03. The researcher is using the standard alpha level of α=.05\alpha = .05.

Question: Explain how the researcher should interpret this pp-value of .03.03 relative to their alpha level, detailing the appropriate decision regarding the null hypothesis and what this decision means for the effectiveness of the new study technique.

Sample answer: Since the obtained pp-value of .03.03 is less than or equal to the alpha level of .05.05, the researcher must reject the null hypothesis. This decision indicates that there is a statistically significant difference in test scores, implying that the new study technique has a significant effect.

Key points:

  • Compare the obtained pp-value (.03.03) to the α=.05\alpha = .05 threshold.
  • State the decision to reject the null hypothesis because the pp-value is less than or equal to .05.05.
  • Conclude that a significant difference exists in test scores between the groups.

Rubric: The response must correctly identify that .03.03 is less than or equal to .05.05, state that the null hypothesis is rejected, and explain that a significant difference exists between the groups, showing the study technique is effective.

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Updated 2026-05-26

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Research Methods in Psychology - 4th American Edition @ KPU

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