Short Answer

Influence of Dimensionality on RoPE Scaling Factor

Given the formula for the RoPE scaling factor λ=(mml)dd2\lambda = \left(\frac{m}{m_l}\right)^{\frac{d}{d-2}} where m is the new sequence length, m_l is the original length, and d is the embedding dimensionality, analyze the effect of the dimensionality d on the scaling factor λ. Specifically, what happens to the exponent d / (d - 2) as d becomes very large, and what does this imply for the value of λ in models with high-dimensional embeddings?

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Updated 2025-10-08

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