Example

Solve an Application using a System of Three Linear Equations (Try It 4.72)

Consider an application of a system of three linear equations where a soccer team sold adult tickets for $1010, student tickets for $88, and child tickets for $55. They sold 600600 tickets and brought in $4,9004{,}900. The number of adult tickets was twice the number of child tickets.

Let xx be the number of adult tickets, yy be the number of student tickets, and zz be the number of child tickets. The system of equations modeling this application is:

{x+y+z=60010x+8y+5z=4900x2z=0\begin{cases} x + y + z = 600 \\\\ 10x + 8y + 5z = 4900 \\\\ x - 2z = 0 \end{cases}

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Updated 2026-05-25

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