Short Answer

Using the provided cookie calorie study variables (M=212.00M = 212.00, SD=39.17SD = 39.17, and n=10n = 10), show the step-by-step application of the tt-statistic formula to compute the final tt-value, including the calculation of the denominator and the numerator.

Question: Using the provided cookie calorie study variables (M=212.00M = 212.00, SD=39.17SD = 39.17, and n=10n = 10), show the step-by-step application of the tt-statistic formula to compute the final tt-value, including the calculation of the denominator and the numerator.

Sample answer: First, calculate the numerator as the difference between the sample mean and the hypothesized mean: 212.00250=38212.00 - 250 = -38. Second, calculate the standard error in the denominator: 39.171012.39\frac{39.17}{\sqrt{10}} \approx 12.39. Finally, divide the numerator by the denominator: 3812.393.07\frac{-38}{12.39} \approx -3.07.

Key points:

  • The numerator is 212.00250=38212.00 - 250 = -38.
  • The denominator (standard error) is calculated as 39.171012.39\frac{39.17}{\sqrt{10}} \approx 12.39.
  • The resulting tt-value is 3.07-3.07.

Feedback: Correct implementation of the formula yields: Numerator = 212.00250=38212.00 - 250 = -38; Denominator = 39.171012.39\frac{39.17}{\sqrt{10}} \approx 12.39; t=3812.39=3.07t = \frac{-38}{12.39} = -3.07.

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Updated 2026-05-27

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Research Methods in Psychology - 4th American Edition @ KPU

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