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Consider a $$t$$ score of $$1.50$$ based on a sample of $$25$$. The probability of a $$t$$ score at least this extreme is given by the proportion of $$t$$ scores in the distribution that are at least this extreme. Defining extreme as being far from zero in either direction, the $$p$$-value is the proportion of $$t$$ scores that are $$1.50$$ or above or that are $$-1.50$$ or below, which is $$.14$$.

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