True/False

A technician is mapping a hyperbolic path defined by the general equation 4x29y224x36y36=0{}4x^2 - 9y^2 - 24x - 36y - 36 = 0. After converting the equation to its standard form, (x3)29(y+2)24=1\frac{(x - 3)^2}{9} - \frac{(y + 2)^2}{4} = 1, the technician identifies the center of the hyperbola at (3, -2). Since the x2x^2 term is positive in the standard form, the technician concludes that the hyperbola opens horizontally and that both vertices will also have a yy-coordinate of -2. Is this statement true or false?

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Updated 2026-05-25

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