Example

Adding and Subtracting vv+1+3v−1−6v2−1\frac{v}{v+1} + \frac{3}{v-1} - \frac{6}{v^2-1}

Simplify the expression vv+1+3v−1−6v2−1\frac{v}{v+1} + \frac{3}{v-1} - \frac{6}{v^2-1}. To add and subtract these rational expressions, first find the Least Common Denominator (LCD). Factor the third denominator, v2−1v^2-1, into (v−1)(v+1)(v-1)(v+1). Thus, the LCD for all three terms is (v−1)(v+1)(v-1)(v+1). Rewrite each fraction with this common denominator: the first term becomes v(v−1)(v+1)(v−1)\frac{v(v-1)}{(v+1)(v-1)}, the second becomes 3(v+1)(v−1)(v+1)\frac{3(v+1)}{(v-1)(v+1)}, and the third remains 6(v−1)(v+1)\frac{6}{(v-1)(v+1)}. Combine the numerators over the common denominator to get v(v−1)+3(v+1)−6(v−1)(v+1)\frac{v(v-1) + 3(v+1) - 6}{(v-1)(v+1)}. Distribute to remove parentheses in the numerator, yielding v2−v+3v+3−6(v−1)(v+1)\frac{v^2 - v + 3v + 3 - 6}{(v-1)(v+1)}. Combine like terms to simplify the numerator to v2+2v−3v^2 + 2v - 3. Factor this trinomial as (v+3)(v−1)(v+3)(v-1). Write the factored expression as (v+3)(v−1)(v−1)(v+1)\frac{(v+3)(v-1)}{(v-1)(v+1)} and divide out the common factor of (v−1)(v-1). The final simplified expression is v+3v+1\frac{v+3}{v+1}.

0

1

Updated 2026-06-03

Contributors are:

Who are from:

Tags

OpenStax

Intermediate Algebra @ OpenStax

Ch.7 Rational Expressions and Functions - Intermediate Algebra @ OpenStax

Algebra

Related
Learn After