Short Answer

Analyzing Components of a Vector Transformation

A transformation is applied to a d-dimensional vector x\mathbf{x} at position tt using a set of frequencies θ\theta. The full transformation is defined by the following element-wise formula: Transfull(x,tθ)=(x1x2xd1xd)(costθ1costθ1costθd/2costθd/2)+(x2x1xdxd1)(sintθ1sintθ1sintθd/2sintθd/2)\mathrm{Trans}_{full}(\mathbf{x}, t\theta) = \begin{pmatrix} x_1 \\ x_2 \\ \vdots \\ x_{d-1} \\ x_d \end{pmatrix} \odot \begin{pmatrix} \cos t\theta_1 \\ \cos t\theta_1 \\ \vdots \\ \cos t\theta_{d/2} \\ \cos t\theta_{d/2} \end{pmatrix} + \begin{pmatrix} -x_2 \\ x_1 \\ \vdots \\ -x_d \\ x_{d-1} \end{pmatrix} \odot \begin{pmatrix} \sin t\theta_1 \\ \sin t\theta_1 \\ \vdots \\ \sin t\theta_{d/2} \\ \sin t\theta_{d/2} \end{pmatrix} Now, consider a simplified version of this transformation where the second term (involving the sine vector) is removed: Transsimple(x,tθ)=(x1x2xd1xd)(costθ1costθ1costθd/2costθd/2)\mathrm{Trans}_{simple}(\mathbf{x}, t\theta) = \begin{pmatrix} x_1 \\ x_2 \\ \vdots \\ x_{d-1} \\ x_d \end{pmatrix} \odot \begin{pmatrix} \cos t\theta_1 \\ \cos t\theta_1 \\ \vdots \\ \cos t\theta_{d/2} \\ \cos t\theta_{d/2} \end{pmatrix} Analyze the effect of this simplification. What geometric property of the full transformation is lost in the simple version, and what operation does the simple version perform instead?

0

1

Updated 2025-10-04

Contributors are:

Who are from:

Tags

Ch.3 Prompting - Foundations of Large Language Models

Foundations of Large Language Models

Foundations of Large Language Models Course

Computing Sciences

Analysis in Bloom's Taxonomy

Cognitive Psychology

Psychology

Social Science

Empirical Science

Science

Related