True/False

As a facilities coordinator for your company, you are verifying the dimensions for a rectangular sign with an area of 30{}30 square feet. The sign's length is designed to be one foot more than its width (ww). After solving the resulting quadratic equation w2+w30=0w^2 + w - 30 = 0, you find two algebraic solutions: w=5w = 5 and w=6w = -6. True or False: Both w=5w = 5 and w=6w = -6 are valid measurements for the physical width of the sign.

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Updated 2026-05-22

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