Example

Choosing the Most Convenient Method for {4x5y=32,  3x+2y=1}\{4x - 5y = -32,\; 3x + 2y = -1\} and {x=2y1,  3x5y=7}\{x = 2y - 1,\; 3x - 5y = -7\}

When choosing an algebraic method to solve a system of linear equations, the most convenient method is determined by the form of the equations. For the system {4x5y=32,  3x+2y=1}\{4x - 5y = -32,\; 3x + 2y = -1\}, both equations are presented in standard form (Ax+By=CAx + By = C), meaning neither variable is already isolated. Therefore, elimination will be the most convenient method. In contrast, for the system {x=2y1,  3x5y=7}\{x = 2y - 1,\; 3x - 5y = -7\}, the first equation is directly solved for the variable xx. Since one equation provides a fully isolated variable, substitution is the most straightforward method to employ.

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Updated 2026-04-24

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Ch.4 Systems of Linear Equations - Intermediate Algebra @ OpenStax

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