Example

Determine if (−2,−1,3)(-2,-1,3) and (−4,−3,4)(-4,-3,4) are Solutions to a System of Three Equations

Given the system of equations: {x−y+z=22x−y−z=−62x+2y+z=−3\begin{cases} x - y + z = 2 2x - y - z = -6 2x + 2y + z = -3 \end{cases} To determine if (−2,−1,3)(-2,-1,3) is a solution, substitute the values into all three equations:

  1. −2−(−1)+3=2-2 - (-1) + 3 = 2
  2. 2(−2)−(−1)−3=−62(-2) - (-1) - 3 = -6
  3. 2(−2)+2(−1)+3=−32(-2) + 2(-1) + 3 = -3 Since it makes all equations true, (−2,−1,3)(-2,-1,3) is a solution. To determine if (−4,−3,4)(-4,-3,4) is a solution, substitute the values into the equations:
  4. −4−(−3)+4=3≠2-4 - (-3) + 4 = 3 \neq 2 Since it does not make the first equation true, (−4,−3,4)(-4,-3,4) is not a solution.

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Updated 2026-06-05

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