Example

Determining if y=75y=\frac{7}{5} is a Solution of 5y+3=10y45y+3=10y-4

To verify if y=75y=\frac{7}{5} is a valid solution to the linear equation 5y+3=10y45y+3=10y-4, apply the three-step determination strategy:

Step 1. Substitute the value for the variable: 5\left(\frac{7}{5} ight) + 3 = 10\left(\frac{7}{5} ight) - 4

Step 2. Simplify expressions on both sides. Multiply first: 7+3=1447 + 3 = 14 - 4. Then simplify: 10=1010 = 10.

Step 3. Determine if the result is true: Since 10=1010 = 10 is a true mathematical statement, the value y=75y=\frac{7}{5} is confirmed as a solution to the equation.

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Updated 2026-05-02

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