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Determining the Domain of the Radical Function f(x)=2x2+33f(x) = \sqrt[3]{2x^2 + 3}

To systematically find the domain of the radical function f(x)=2x2+33f(x) = \sqrt[3]{2x^2 + 3}, first examine the index of the radical. The index is 33, which is an odd number. Because the root of an odd-indexed radical is a real number for any real value of its radicand, the expression inside the radical imposes no restrictions. Therefore, the radicand 2x2+32x^2 + 3 can legally be any real number, meaning the domain of the function consists of all real numbers. In interval notation, this domain is correctly written as (,)(-\infty, \infty).

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Updated 2026-05-25

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