Example

Evaluating (f⋅g)(2)(f \cdot g)(2) for f(x)=x−5f(x) = x - 5 and g(x)=x2−2x+3g(x) = x^2 - 2x + 3

To evaluate (f⋅g)(2)(f \cdot g)(2) for the functions f(x)=x−5f(x) = x - 5 and g(x)=x2−2x+3g(x) = x^2 - 2x + 3, first use the product function (f⋅g)(x)=x3−7x2+13x−15(f \cdot g)(x) = x^3 - 7x^2 + 13x - 15. Substitute x=2x = 2 into this polynomial: (f⋅g)(2)=23−7(2)2+13(2)−15(f \cdot g)(2) = 2^3 - 7(2)^2 + 13(2) - 15. Simplifying the expression yields 8−28+26−158 - 28 + 26 - 15, which sums to −9-9. Therefore, (f⋅g)(2)=−9(f \cdot g)(2) = -9.

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Updated 2026-06-03

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