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Example: Finding the Fourteenth Term of a Geometric Sequence
Find the fourteenth term of a geometric sequence where the first term is and the common ratio is .
Use the general term formula with , , and :
Substitute the values:
ight)^{14-1}$$ Simplify the exponent: $$a_{14} = 64 \left(\frac{1}{2} ight)^{13}$$ Evaluate: $$a_{14} = \frac{1}{128}$$ The fourteenth term of the sequence is $$\frac{1}{128}$$.0
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Ch.12 Sequences, Series and Binomial Theorem - Intermediate Algebra @ OpenStax
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Example: Finding the Fourteenth Term of a Geometric Sequence
Example: Finding the Twelfth Term and General Term of a Geometric Sequence
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