Example

Example: Finding the Fourteenth Term of a Geometric Sequence

Find the fourteenth term of a geometric sequence where the first term is 6464 and the common ratio is r=12r = \frac{1}{2}.

Use the general term formula with a1=64a_1 = 64, r=12r = \frac{1}{2}, and n=14n = 14:

an=a1rn1a_n = a_1 r^{n-1}

Substitute the values:

ight)^{14-1}$$ Simplify the exponent: $$a_{14} = 64 \left(\frac{1}{2} ight)^{13}$$ Evaluate: $$a_{14} = \frac{1}{128}$$ The fourteenth term of the sequence is $$\frac{1}{128}$$.

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Updated 2026-05-25

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