Example

Example: Finding the Sum of the First 30 Terms of an Arithmetic Sequence

Find the sum of the first 30 terms of the arithmetic sequence 8,13,18,23,28,…8, 13, 18, 23, 28, \dots

To compute this sum, use the formula Sn=n2(a1+an)S_n = \frac{n}{2}(a_1 + a_n). The known values are a1=8a_1 = 8, d=5d = 5, and n=30n = 30, but ana_n must be found first.

Use the general term formula to find a30a_{30}:

an=a1+(nβˆ’1)da_n = a_1 + (n - 1)d

a30=8+(30βˆ’1)β‹…5a_{30} = 8 + (30 - 1) \cdot 5

a30=8+(29)β‹…5a_{30} = 8 + (29) \cdot 5

a30=8+145=153a_{30} = 8 + 145 = 153

Now substitute a1=8a_1 = 8, n=30n = 30, and a30=153a_{30} = 153 into the sum formula:

Sn=n2(a1+an)S_n = \frac{n}{2}(a_1 + a_n)

S30=302(8+153)S_{30} = \frac{30}{2}(8 + 153)

S30=15(161)S_{30} = 15(161)

S30=2,415S_{30} = 2{,}415

The sum of the first 30 terms is 2,4152{,}415. This example illustrates a two-step process commonly needed when applying the sum formula: first using the general term formula an=a1+(nβˆ’1)da_n = a_1 + (n - 1)d to determine the last term, then substituting all known values into the sum formula Sn=n2(a1+an)S_n = \frac{n}{2}(a_1 + a_n).

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Updated 2026-05-25

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Ch.12 Sequences, Series and Binomial Theorem - Intermediate Algebra @ OpenStax

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