Example

Example: Solving a Coin Mixture Problem with Quarters and Nickels

Apply the problem-solving strategy to find the number of each type of coin based on their total value and a relationship involving multiplication and addition.

Problem: Jesse has $6.55 worth of quarters and nickels in his pocket. The number of nickels is five more than two times the number of quarters. How many nickels and how many quarters does Jesse have?

  1. Read: The coins are quarters (worth $0.25) and nickels (worth $0.05). The total value is $6.55.
  2. Identify: Find the number of quarters and nickels.
  3. Name: Let qq = the number of quarters. The number of nickels is 2q+52q + 5.
TypeNumberValue ($)Total Value ($)
Quartersqq0.250.250.25q0.25q
Nickels2q+52q + 50.050.050.05(2q+5)0.05(2q + 5)
  1. Translate: Add the total values to equal $6.55: 0.25q+0.05(2q+5)=6.550.25q + 0.05(2q + 5) = 6.55
  2. Solve:
  • Distribute 0.050.05: 0.25q+0.10q+0.25=6.550.25q + 0.10q + 0.25 = 6.55
  • Combine like terms: 0.35q+0.25=6.550.35q + 0.25 = 6.55
  • Subtract 0.250.25 from both sides: 0.35q=6.300.35q = 6.30
  • Divide both sides by 0.350.35: q=18q = 18 Find the number of nickels: 2(18)+5=36+5=412(18) + 5 = 36 + 5 = 41
  1. Check: Does 18(0.25)+41(0.05)=6.5518(0.25) + 41(0.05) = 6.55? 4.50+2.05=6.554.50 + 2.05 = 6.55 \checkmark
  2. Answer: Jesse has 1818 quarters and 4141 nickels.

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Updated 2026-04-22

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