Example

Example: Solving a Destination Wedding Budget Application with a Linear Inequality

To calculate the amount of work needed to afford a trip for an event like a destination wedding, apply the linear inequality word problem strategy. For example, Brenda needs to pay for 33 nights at a hotel at $60 per night, $350 for airfare, and $375 for food and entertainment. She has $500 in savings and earns $15 an hour babysitting. Let hh be the number of babysitting hours. Translating the requirement that expenses must be less than or equal to total available funds yields: 350+375+60(3)≤500+15h350 + 375 + 60(3) \leq 500 + 15h. Solving for hh, first simplify the left side to get 350+375+180≤500+15h350 + 375 + 180 \leq 500 + 15h, which is 905≤500+15h905 \leq 500 + 15h. Subtracting 500500 from both sides yields 405≤15h405 \leq 15h. Dividing by 1515 gives 27≤h27 \leq h, or h≥27h \geq 27. Brenda must babysit at least 2727 hours to have enough money to pay for the trip.

0

1

Updated 2026-06-29

Tags

OpenStax

Intermediate Algebra @ OpenStax

Ch.2 Solving Linear Equations - Intermediate Algebra @ OpenStax

Algebra

Related