Example

Example: Solving and Graphing 8p+3(p12)>7p288p + 3(p - 12) > 7p - 28

To solve the inequality 8p+3(p12)>7p288p + 3(p - 12) > 7p - 28, first simplify each side by distributing to get 8p+3p36>7p288p + 3p - 36 > 7p - 28, which condenses to 11p36>7p2811p - 36 > 7p - 28. Next, collect the variables on the left side by subtracting 7p7p from both sides to obtain 4p36>284p - 36 > -28. Add 3636 to both sides to collect the constants on the right, yielding 4p>84p > 8. Divide both sides by 44. Since 44 is notably positive, the inequality symbol remains exactly the same, culminating in p>2p > 2. Graph the solution on the number line with a left parenthesis at 22 and shading stretching to the right. In interval notation, the solution is written securely as (2,)(2, \infty).

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Updated 2026-04-22

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