Example

Example: Solving and Graphing rβˆ’13≀712r - \frac{1}{3} \leq \frac{7}{12}

To solve the linear inequality rβˆ’13≀712r - \frac{1}{3} \leq \frac{7}{12}, apply the Addition Property of Inequality by adding 13\frac{1}{3} to both sides. Finding a common denominator allows for combining the fractions: 712+412=1112\frac{7}{12} + \frac{4}{12} = \frac{11}{12}. Thus, the inequality simplifies to r≀1112r \leq \frac{11}{12}. Graphing this on a number line requires placing a right bracket at 1112\frac{11}{12} and shading to the left. The solution is written in interval notation as (βˆ’βˆž,1112](-\infty, \frac{11}{12}].

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Updated 2026-04-22

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Ch.2 Solving Linear Equations - Intermediate Algebra @ OpenStax

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