Learn Before
Example

Example 10.42: Solving 3ex+2=243e^{x+2} = 24

To solve the exponential equation 3ex+2=243e^{x+2} = 24, first isolate the exponential term by dividing both sides by 33, which gives ex+2=8e^{x+2} = 8. Since the base is ee, take the natural logarithm of both sides to obtain lnex+2=ln8\ln e^{x+2} = \ln 8. Apply the Power Property of Logarithms to bring the exponent to the front, resulting in (x+2)lne=ln8(x+2)\ln e = \ln 8. Because lne=1\ln e = 1, the equation simplifies to x+2=ln8x+2 = \ln 8. Subtracting 22 from both sides yields the exact solution x=ln82x = \ln 8 - 2. Using a calculator, this value approximates to 0.0790.079.

0

1

Updated 2026-05-26

Contributors are:

Who are from:

Tags

OpenStax

Intermediate Algebra @ OpenStax

Ch.10 Exponential and Logarithmic Functions - Intermediate Algebra @ OpenStax

Algebra