Example

Factoring 8u2−17u−218u^2 - 17u - 21 Using the ac Method

Factor 8u2−17u−218u^2 - 17u - 21 by applying the ac method, demonstrating the process when the constant term is negative and the product a⋅ca \cdot c is a large negative number.

Step 1 — Factor any GCF. The terms 8u28u^2, −17u-17u, and −21-21 share no common factor, so proceed to the next step.

Step 2 — Find the product acac. Here a=8a = 8 and c=−21c = -21, so ac=8(−21)=−168ac = 8(-21) = -168.

Step 3 — Find two numbers that multiply to −168-168 and add to −17-17. Because the product is negative, the two numbers must have opposite signs, and because the sum is negative, the factor with the larger absolute value must be negative. List factor pairs of −168-168 and check their sums:

Factors of −168-168Sum of factors
1,−1681, -1681+(−168)=−1671 + (-168) = -167
2,−842, -842+(−84)=−822 + (-84) = -82
3,−563, -563+(−56)=−533 + (-56) = -53
4,−424, -424+(−42)=−384 + (-42) = -38
6,−286, -286+(−28)=−226 + (-28) = -22
7,−247, -247+(−24)=−177 + (-24) = -17 ✓
8,−218, -218+(−21)=−138 + (-21) = -13

The pair 77 and −24-24 works: 7⋅(−24)=−1687 \cdot (-24) = -168 and 7+(−24)=−177 + (-24) = -17.

Step 4 — Split the middle term −17u-17u into 7u7u and −24u-24u:

8u2−17u−21=8u2+7u−24u−218u^2 - 17u - 21 = 8u^2 + 7u - 24u - 21

Step 5 — Factor by grouping. Group into two pairs and factor the GCF from each:

u(8u+7)−3(8u+7)u(8u + 7) - 3(8u + 7)

Both groups share the common binomial (8u+7)(8u + 7). Factor it out:

(8u+7)(u−3)(8u + 7)(u - 3)

Step 6 — Check by multiplying: (8u+7)(u−3)=8u2−24u+7u−21=8u2−17u−21(8u + 7)(u - 3) = 8u^2 - 24u + 7u - 21 = 8u^2 - 17u - 21 ✓

The factored form is (8u+7)(u−3)(8u + 7)(u - 3). Unlike the earlier example of 6x2+7x+26x^2 + 7x + 2 where acac was positive, here the negative constant produces a negative acac product of −168-168, which means the two numbers mm and nn must have opposite signs. Additionally, because the middle coefficient −17-17 is negative, the larger factor (in absolute value) must carry the negative sign. This example also illustrates that the factor-pair search may involve many rows when ∣ac∣|ac| is large.

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Updated 2026-04-21

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