Example

Factoring 36x2+84xy+49y236x^2 + 84xy + 49y^2

Factor 36x2+84xy+49y236x^2 + 84xy + 49y^2 by recognizing it as a perfect square trinomial in two variables.

Step 1 — Check whether the trinomial fits the pattern a2+2ab+b2a^2 + 2ab + b^2:

  • Is the first term a perfect square? Yes: 36x2=(6x)236x^2 = (6x)^2, so a=6xa = 6x.
  • Is the last term a perfect square? Yes: 49y2=(7y)249y^2 = (7y)^2, so b=7yb = 7y.
  • Is the middle term 2ab2ab? Check: 26x7y=84xy2 \cdot 6x \cdot 7y = 84xy. Yes, the middle term is 84xy84xy. ✓

Step 2 — Write the square of the binomial: Since the trinomial matches the addition pattern with a=6xa = 6x and b=7yb = 7y:

36x2+84xy+49y2=(6x)2+2(6x)(7y)+(7y)2=(6x+7y)236x^2 + 84xy + 49y^2 = (6x)^2 + 2(6x)(7y) + (7y)^2 = (6x + 7y)^2

Step 3 — Check by multiplying: (6x+7y)2=(6x)2+26x7y+(7y)2=36x2+84xy+49y2(6x + 7y)^2 = (6x)^2 + 2 \cdot 6x \cdot 7y + (7y)^2 = 36x^2 + 84xy + 49y^2 ✓.

The factored form is (6x+7y)2(6x + 7y)^2. This example extends the Perfect Square Trinomials Pattern to a trinomial with two variables. Both the first and last terms involve squaring a monomial with a variable — (6x)2=36x2(6x)^2 = 36x^2 and (7y)2=49y2(7y)^2 = 49y^2 — and the middle term 84xy84xy contains the product of both variables. Recognizing the perfect square structure allows direct factoring into the square of a two-variable binomial.

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Updated 2026-04-21

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