Example

Finding the Equation of a Line Perpendicular to y=3y = -3 Through (3,5)(-3, 5)

To construct the algebraic equation characterizing a line directed perpendicularly to y=3y = -3 and passing through the coordinate pair (3,5)(-3, 5), leverage the geometry of horizontal alignments. The line y=3y = -3 establishes a consistently flat horizontal line. Any line carving a perpendicular angle through a horizontal line translates into a vertical line geometry formatted as x=ax = a. Since this navigating vertical span projects straight through the destination point (3,5)(-3, 5), every dot tracked along its path locks into the uniform xx-coordinate of 3-3. Conclusively, the finalized algebraic equation resolving the perpendicular trajectory is firmly determined as x=3x = -3.

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Updated 2026-05-03

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