Example

Finding the GCF of 25m425m^4, 35m335m^3, and 20m220m^2

To find the greatest common factor of 25m425m^4, 35m335m^3, and 20m220m^2, apply the prime factorization method to both the coefficients and the variables.

Step 1 β€” Factor coefficients and expand variables: Write 25m4=5β‹…5β‹…mβ‹…mβ‹…mβ‹…m25m^4 = 5 \cdot 5 \cdot m \cdot m \cdot m \cdot m, 35m3=5β‹…7β‹…mβ‹…mβ‹…m35m^3 = 5 \cdot 7 \cdot m \cdot m \cdot m, and 20m2=2β‹…2β‹…5β‹…mβ‹…m20m^2 = 2 \cdot 2 \cdot 5 \cdot m \cdot m.

Step 2 β€” Align factors in columns and circle the common ones: The shared factors are one 55 and two mms (i.e., 5,m,m5, m, m).

Step 3 β€” Bring down the common factors: Collect 5β‹…mβ‹…m5 \cdot m \cdot m.

Step 4 β€” Multiply: 5β‹…mβ‹…m=5m25 \cdot m \cdot m = 5m^2.

The GCF of 25m425m^4, 35m335m^3, and 20m220m^2 is 5m25m^2.

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Updated 2026-04-29

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