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Finding the Quotient
Divide a trinomial by a variable monomial where one term does not contain the variable: .
Step 1 — Separate the terms. Split the fraction so that each term of the numerator is divided individually by the denominator: .
Step 2 — Simplify each fraction. For the first term: divide the coefficients and apply the Quotient Property , giving . For the second term: (both the coefficient and the variable cancel completely). For the third term: divide the coefficients , but the numerator has no variable to cancel with the in the denominator, so the variable remains below the fraction bar: .
The quotient is . This example illustrates that when a polynomial term (here, the constant ) does not contain the variable present in the monomial divisor, the simplified fraction retains that variable in its denominator rather than producing a whole-number or polynomial term.
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Ch.6 Polynomials - Elementary Algebra @ OpenStax
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Finding the Quotient
Finding the Quotient
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Finding the Quotient
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Learn After
In a production cost analysis, a technician simplifies the expression (10x^2 + 5x - 20) / 5x. According to the rules of polynomial division, how should the constant term -20 be represented in the final simplified quotient after being divided by 5x?
A technician is simplifying the expression (10x^2 + 5x - 20) / 5x to analyze production costs. Match each individual term from the numerator, when divided by the denominator 5x, with its correctly simplified form.
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An operations analyst is simplifying the efficiency expression for a department report. True or False: In the final simplified quotient, the middle term is because the in the numerator and the in the denominator cancel out completely.
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A logistics coordinator is simplifying the shipping cost expression for a budget report. After dividing each term of the numerator individually by the denominator, the coordinator finds that the result of simplifying the constant term divided by is ____.
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An inventory specialist at a distribution center is simplifying the average storage cost expression , where represents the number of units. According to the rules for dividing a polynomial by a monomial, why does the variable remain in the denominator of the simplified constant term ()?
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