Example

Finding the Quotient (125x3−8)÷(5x−2)(125x^3 - 8) \div (5x - 2)

Apply polynomial long division to divide a two-term polynomial by a binomial whose leading coefficient is not 11, utilizing placeholders for multiple missing degree terms: (125x3−8)÷(5x−2)(125x^3 - 8) \div (5x - 2).

Step 1 — Insert placeholders. The dividend 125x3−8125x^3 - 8 jumps from degree 3 directly to degree 0, meaning it is missing both the x2x^2 and xx terms. Rewrite it with placeholders: 125x3+0x2+0x−8125x^3 + 0x^2 + 0x - 8. Set this up under the division bracket with 5x−25x - 2 outside.

Step 2 — Divide 125x3125x^3 by 5x5x. The result is 25x225x^2. Write 25x225x^2 in the quotient. Multiply 25x2(5x−2)=125x3−50x225x^2(5x - 2) = 125x^3 - 50x^2. Subtract (125x3+0x2)−(125x3−50x2)=50x2(125x^3 + 0x^2) - (125x^3 - 50x^2) = 50x^2. Bring down 0x0x to form 50x2+0x50x^2 + 0x.

Step 3 — Divide 50x250x^2 by 5x5x. The result is 10x10x. Write 10x10x in the quotient. Multiply 10x(5x−2)=50x2−20x10x(5x - 2) = 50x^2 - 20x. Subtract (50x2+0x)−(50x2−20x)=20x(50x^2 + 0x) - (50x^2 - 20x) = 20x. Bring down −8-8 to form 20x−820x - 8.

Step 4 — Divide 20x20x by 5x5x. The result is 44. Write 44 in the quotient. Multiply 4(5x−2)=20x−84(5x - 2) = 20x - 8. Subtract (20x−8)−(20x−8)=0(20x - 8) - (20x - 8) = 0.

The quotient is 25x2+10x+425x^2 + 10x + 4.

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Updated 2026-06-17

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