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Functional Derivative Identity for Integrals

For a differentiable function f(x)f(\mathbf{x}) and a differentiable function g(y,x)g(y, \mathbf{x}) with continuous derivatives, the functional derivative of the integral of g(f(x),x)g(f(\mathbf{x}), \mathbf{x}) is given by:

f(x)g(f(x),x)dx=yg(f(x),x)\frac{\partial}{\partial f(\mathbf{x})} \int g(f(\mathbf{x}), \mathbf{x}) d\mathbf{x} = \frac{\partial}{\partial y} g(f(\mathbf{x}), \mathbf{x})

A useful way to think about this identity is to compare f(x)f(\mathbf{x}) to a vector with infinite elements whose values are indexed by x\mathbf{x}. Under this analogy, the identity can be compared to the discrete partial derivative for a vector θ\boldsymbol{\theta}:

θijg(θj,j)=θig(θi,i)\frac{\partial}{\partial \theta_i} \sum_j g(\theta_j, j) = \frac{\partial}{\partial \theta_i} g(\theta_i, i)

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Updated 2026-06-19

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