Example

Multiplying (3xy)(3x+y)(3x - y)(3x + y) Using the Product of Conjugates Pattern

Apply the Product of Conjugates Pattern to multiply (3xy)(3x+y)(3x - y)(3x + y). Both binomials share the same first term 3x3x and the same last term yy, with one using subtraction and the other addition, confirming they are conjugates. Use the formula (ab)(a+b)=a2b2(a - b)(a + b) = a^2 - b^2, where a=3xa = 3x and b=yb = y.

Step 1 — Square the first term, 3x3x: (3x)2=9x2(3x)^2 = 9x^2. Square the coefficient and the variable separately: 32=93^2 = 9 and x2=x2x^2 = x^2. Step 2 — Square the last term, yy: y2=y2y^2 = y^2. Step 3 — Write the difference of squares: (3xy)(3x+y)=9x2y2(3x - y)(3x + y) = 9x^2 - y^2

The product is 9x2y29x^2 - y^2.

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Updated 2026-05-26

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