Example

Multiplying (3xβˆ’y)(3x+y)(3x - y)(3x + y) Using the Product of Conjugates Pattern

Apply the Product of Conjugates Pattern to multiply (3xβˆ’y)(3x+y)(3x - y)(3x + y). Both binomials share the same first term 3x3x and the same last term yy, with one using subtraction and the other addition, confirming they are conjugates. Use the formula (aβˆ’b)(a+b)=a2βˆ’b2(a - b)(a + b) = a^2 - b^2, where a=3xa = 3x and b=yb = y.

Step 1 β€” Square the first term, 3x3x: (3x)2=9x2(3x)^2 = 9x^2. Square the coefficient and the variable separately: 32=93^2 = 9 and x2=x2x^2 = x^2. Step 2 β€” Square the last term, yy: y2=y2y^2 = y^2. Step 3 β€” Write the difference of squares: (3xβˆ’y)(3x+y)=9x2βˆ’y2(3x - y)(3x + y) = 9x^2 - y^2

The product is 9x2βˆ’y29x^2 - y^2.

0

1

Updated 2026-04-29

Contributors are:

Who are from:

Tags

OpenStax

Intermediate Algebra @ OpenStax

Ch.5 Polynomials and Polynomial Functions - Intermediate Algebra @ OpenStax

Algebra

Related