Example

Multiplying (3y−1)(2y−6)(3y - 1)(2y - 6) Using the Vertical Method

Multiply (3y−1)(2y−6)(3y - 1)(2y - 6) using the Vertical Method — the process mirrors multi-digit whole-number multiplication, with partial products aligned by like terms.

Step 1 — Set up vertically: Write one binomial above the other (it does not matter which goes on top):

3y−13y - 1 ×2y−6\times \quad 2y - 6

Step 2 — Multiply the top binomial by −6-6: Multiply each term of 3y−13y - 1 by −6-6:

(−6)(3y)=−18y(-6)(3y) = -18y and (−6)(−1)=6(-6)(-1) = 6

Write the first partial product: −18y+6-18y + 6.

Step 3 — Multiply the top binomial by 2y2y: Multiply each term of 3y−13y - 1 by 2y2y:

(2y)(3y)=6y2(2y)(3y) = 6y^2 and (2y)(−1)=−2y(2y)(-1) = -2y

Write the second partial product: 6y2−2y6y^2 - 2y, aligning like terms beneath the first partial product.

Step 4 — Add the partial products: Combine like terms column by column. The y2y^2 column has 6y26y^2. The yy column has −18y+(−2y)=−20y-18y + (-2y) = -20y. The constant column has 66:

6y2−20y+66y^2 - 20y + 6

The result is 6y2−20y+66y^2 - 20y + 6. The partial products −18y+6-18y + 6 and 6y2−2y6y^2 - 2y are exactly the same four terms produced by the FOIL method, just arranged vertically with like terms aligned in columns instead of written in a single row.

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Updated 2026-04-21

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