Example

Simplifying 715823157\frac{7}{15} \cdot \frac{8}{23} \cdot \frac{15}{7} Using the Inverse Property of Multiplication

Simplify the product of three fractions by recognizing a reciprocal pair and reordering factors:

715823157\frac{7}{15} \cdot \frac{8}{23} \cdot \frac{15}{7}

Step 1 — Spot the reciprocals: The first factor 715\frac{7}{15} and the third factor 157\frac{15}{7} are reciprocals of each other, because their numerators and denominators are swapped.

Step 2 — Reorder using the commutative property of multiplication: Swap the second and third factors so that the reciprocal pair sits side by side:

715157823\frac{7}{15} \cdot \frac{15}{7} \cdot \frac{8}{23}

Step 3 — Apply the inverse property of multiplication: The reciprocal pair multiplies to 11:

18231 \cdot \frac{8}{23}

Step 4 — Apply the multiplicative identity: Multiplying by 11 leaves the remaining fraction unchanged:

823\frac{8}{23}

This example mirrors the addition strategy of scanning for additive inverses (opposites), but in a multiplication setting: before multiplying left to right, look for factors that are reciprocals. Rearranging them next to each other allows them to collapse to 11, simplifying the computation in fewer steps.

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Updated 2026-04-21

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