Example

Simplifying 715β‹…823β‹…157\frac{7}{15} \cdot \frac{8}{23} \cdot \frac{15}{7}

To simplify the product 715β‹…823β‹…157\frac{7}{15} \cdot \frac{8}{23} \cdot \frac{15}{7}, observe that the first and third fractions are reciprocals. Apply the commutative property of multiplication to reorder the factors so the reciprocals are adjacent: 715β‹…157β‹…823\frac{7}{15} \cdot \frac{15}{7} \cdot \frac{8}{23}. Multiplying the reciprocals yields 11 (since their product is the multiplicative identity), simplifying the expression to 1β‹…8231 \cdot \frac{8}{23}. Finally, multiplying by 11 leaves the remaining fraction unchanged, giving the result 823\frac{8}{23}.

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Updated 2026-05-02

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