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Simplifying (106p3)(43p)(10\sqrt{6p^3})(4\sqrt{3p}) and (220y24)(328y34)(2\sqrt[4]{20y^2})(3\sqrt[4]{28y^3})

Multiply and simplify products of radicals that have numerical coefficients and variable radicands.

ⓐ (106p3)(43p)(10\sqrt{6p^3})(4\sqrt{3p}): Multiply the coefficients together and the radicands together: (106p3)(43p)=4018p4(10\sqrt{6p^3})(4\sqrt{3p}) = 40\sqrt{18p^4} Simplify the resulting radical by extracting the largest perfect square factor (9p49p^4): 4018p4=409p4⋅240\sqrt{18p^4} = 40\sqrt{9p^4} \cdot \sqrt{2} Simplify the perfect square and multiply it with the outside coefficient: 40⋅3p2⋅2=120p2240 \cdot 3p^2 \cdot \sqrt{2} = 120p^2\sqrt{2}

ⓑ (220y24)(328y34)(2\sqrt[4]{20y^2})(3\sqrt[4]{28y^3}): Multiply the coefficients and the radicands: (220y24)(328y34)=6560y54(2\sqrt[4]{20y^2})(3\sqrt[4]{28y^3}) = 6\sqrt[4]{560y^5} When the radicands involve large numbers, it is often advantageous to factor them to find perfect powers (560=16⋅35560 = 16 \cdot 35). Identify the largest perfect fourth power factors: 616y4⋅35y4=616y44⋅35y46\sqrt[4]{16y^4 \cdot 35y} = 6\sqrt[4]{16y^4} \cdot \sqrt[4]{35y} Simplify the perfect fourth power and multiply: 6⋅2y35y4=12y35y46 \cdot 2y\sqrt[4]{35y} = 12y\sqrt[4]{35y}

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Updated 2026-06-17

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