Apply the problem-solving strategy for work applications to find how long it takes an individual to lay a concrete slab alone. If Tracy can lay the slab in $3$ hours alone, let $t$ be the number of hours it takes Jordan to lay it alone. In $1$ hour, Tracy lays $\frac{1}{3}$ of the slab, and Jordan lays $\frac{1}{t}$ of the slab. Since it takes them $2$ hours working together, their combined hourly rate is $\frac{1}{2}$ of the slab. The rational equation is: $\frac{1}{3} + \frac{1}{t} = \frac{1}{2}$ Multiply both sides by the least common denominator, $6t$: 6t \left(\frac{1}{3} + \frac{1}{t} ight) = 6t \left(\frac{1}{2} ight) Distribute and simplify: $2t + 6 = 3t$ Subtract $2t$ from both sides: $t = 6$ It would take Jordan $6$ hours to lay the slab alone.