Example

Solving 1a+1b=c\frac{1}{a} + \frac{1}{b} = c for aa

To solve 1a+1b=c\frac{1}{a} + \frac{1}{b} = c for aa: 1. Note restrictions: aeq0,beq0a eq 0, b eq 0. 2. Clear fractions: Multiply by the LCD abab to get b+a=abcb + a = abc. 3. Collect target terms: Move all aa terms to one side: b=abcab = abc - a. 4. Factor: b=a(bc1)b = a(bc - 1). 5. Isolate aa: Divide by (bc1)(bc-1) to get a=bbc1a = \frac{b}{bc-1}.

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Updated 2026-04-30

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