Example

Solving 23u2+5=17\frac{2}{3}u^2 + 5 = 17 Using the Square Root Property

Solve 23u2+5=17\frac{2}{3}u^2 + 5 = 17 by applying the four-step procedure for the Square Root Property. This equation requires subtracting a constant and multiplying by a reciprocal before the property can be used, and the resulting radical must be simplified.

Step 1 — Isolate the quadratic term and make its coefficient one. Subtract 55 from both sides:

23u2=12\frac{2}{3}u^2 = 12

The coefficient of u2u^2 is 23\frac{2}{3}. Multiply both sides by the reciprocal 32\frac{3}{2}:

3223u2=3212\frac{3}{2} \cdot \frac{2}{3}u^2 = \frac{3}{2} \cdot 12

u2=18u^2 = 18

Step 2 — Apply the Square Root Property:

u=±18u = \pm\sqrt{18}

Step 3 — Simplify the radical. The largest perfect square factor of 1818 is 99. Rewrite 1818 as 929 \cdot 2 and apply the Product Property:

18=92=32\sqrt{18} = \sqrt{9} \cdot \sqrt{2} = 3\sqrt{2}

Therefore u=±32u = \pm 3\sqrt{2}.

Rewrite to show two solutions: u=32u = 3\sqrt{2} or u=32u = -3\sqrt{2}.

Step 4 — Check both solutions by substituting into the original equation:

For u=32u = 3\sqrt{2}: 23(32)2+5=23(92)+5=23(18)+5=12+5=17\frac{2}{3}(3\sqrt{2})^2 + 5 = \frac{2}{3}(9 \cdot 2) + 5 = \frac{2}{3}(18) + 5 = 12 + 5 = 17

For u=32u = -3\sqrt{2}: 23(32)2+5=23(92)+5=23(18)+5=12+5=17\frac{2}{3}(-3\sqrt{2})^2 + 5 = \frac{2}{3}(9 \cdot 2) + 5 = \frac{2}{3}(18) + 5 = 12 + 5 = 17

The solutions are u=32u = 3\sqrt{2} and u=32u = -3\sqrt{2}. When the coefficient of the squared term is a fraction, multiplying both sides by the reciprocal is the most efficient way to obtain a coefficient of 11. This example also shows that the resulting constant may not be a perfect square, requiring simplification of the radical using the Product Property of Square Roots.

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Updated 2026-04-21

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