Example

Solving 8q<32-8q < 32 and k1215\frac{k}{-12} \leq 15

Solve each inequality by applying the appropriate property of inequality, reversing the inequality sign when multiplying or dividing by a negative number.

ⓐ Solve 8q<32-8q < 32: Divide both sides by 8-8. Since 8-8 is negative, the inequality reverses: q>4q > -4 In interval notation, the solution is (4,)(-4, \infty).

ⓑ Solve k1215\frac{k}{-12} \leq 15: Multiply both sides by 12-12. Since 12-12 is negative, the inequality reverses: k180k \geq -180 In interval notation, the solution is [180,)[-180, \infty).

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Updated 2026-04-22

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