Example

Solving −8q<32-8q < 32 and k−12≤15\frac{k}{-12} \leq 15

Solve each inequality by applying the appropriate property of inequality, reversing the inequality sign when multiplying or dividing by a negative number.

ⓐ Solve −8q<32-8q < 32: Divide both sides by −8-8. Since −8-8 is negative, the inequality reverses: q>−4q > -4 In interval notation, the solution is (−4,∞)(-4, \infty).

ⓑ Solve k−12≤15\frac{k}{-12} \leq 15: Multiply both sides by −12-12. Since −12-12 is negative, the inequality reverses: k≥−180k \geq -180 In interval notation, the solution is [−180,∞)[-180, \infty).

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Updated 2026-06-03

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