Example

Solving 10[38(2s5)]=15(405s)10[3 - 8(2s - 5)] = 15(40 - 5s) with Nested Grouping Symbols

To solve the linear equation 10[38(2s5)]=15(405s)10[3 - 8(2s - 5)] = 15(40 - 5s), we first simplify the expression starting from the innermost parentheses. By distributing 8-8 into (2s5)(2s - 5), we obtain 10[316s+40]=15(405s)10[3 - 16s + 40] = 15(40 - 5s). Combining like terms inside the brackets gives 10[4316s]=15(405s)10[43 - 16s] = 15(40 - 5s). Distributing the outer factors on both sides yields 430160s=60075s430 - 160s = 600 - 75s. Adding 160s160s to both sides groups the variable terms on the right, creating 430=600+85s430 = 600 + 85s. Subtracting 600600 from both sides groups the constant terms on the left to yield 170=85s-170 = 85s. Finally, dividing both sides by 8585 results in the solution s=2s = -2. Checking the solution by substituting s=2s = -2 into the original equation results in 750=750750 = 750, confirming it is correct.

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Updated 2026-05-02

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