Example

Subtracting 4x211x+8x23x+23x2+x3x23x+2\frac{4x^2-11x+8}{x^2-3x+2} - \frac{3x^2+x-3}{x^2-3x+2}

Subtract two rational expressions that share the common denominator x23x+2x^2-3x+2:

4x211x+8x23x+23x2+x3x23x+2\frac{4x^2-11x+8}{x^2-3x+2} - \frac{3x^2+x-3}{x^2-3x+2}

Step 1 — Subtract the numerators over the common denominator. Place the second numerator in parentheses and write the difference over the shared denominator:

4x211x+8(3x2+x3)x23x+2\frac{4x^2-11x+8 - (3x^2+x-3)}{x^2-3x+2}

Step 2 — Distribute the negative sign in the numerator. Multiply each term inside the parentheses by 1-1, changing +3x2+3x^2 to 3x2-3x^2, +x+x to x-x, and 3-3 to +3+3:

4x211x+83x2x+3x23x+2\frac{4x^2-11x+8 - 3x^2 - x + 3}{x^2-3x+2}

Step 3 — Combine like terms in the numerator. Group the x2x^2-terms: 4x23x2=x24x^2 - 3x^2 = x^2. Group the xx-terms: 11xx=12x-11x - x = -12x. Group the constants: 8+3=118 + 3 = 11:

x212x+11x23x+2\frac{x^2-12x+11}{x^2-3x+2}

Step 4 — Factor both the numerator and the denominator. The numerator x212x+11x^2-12x+11 factors as (x1)(x11)(x-1)(x-11), since (1)+(11)=12(-1) + (-11) = -12 and (1)(11)=11(-1)(-11) = 11. The denominator x23x+2x^2-3x+2 factors as (x1)(x2)(x-1)(x-2), since (1)+(2)=3(-1) + (-2) = -3 and (1)(2)=2(-1)(-2) = 2:

(x1)(x11)(x1)(x2)\frac{(x-1)(x-11)}{(x-1)(x-2)}

Step 5 — Simplify by removing the common factor. Cancel the shared factor (x1)(x-1) from the numerator and denominator:

x11x2\frac{x-11}{x-2}

This example reinforces the procedure of subtracting rational expressions with a common denominator, distributing the negative sign across a trinomial numerator, and factoring both the resulting numerator and the common denominator to identify and cancel common factors.

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Updated 2026-04-30

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Ch.7 Rational Expressions and Functions - Intermediate Algebra @ OpenStax

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