True/False

True or False: When solving the compound inequality 2(3x+1)20{}2(3x+1) \leq 20 and 4(x1)<2{}4(x-1) < 2, the solution to the first inequality is x3x \leq 3 and the solution to the second inequality is x<32x < \frac{3}{2}.

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Updated 2026-05-25

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