To practice solving a compound inequality, solve $2(3x+1) \leq 20$ and $4(x-1) < 2$. Solving the first inequality gives $6x + 2 \leq 20$, which simplifies to $6x \leq 18$ or $x \leq 3$. Solving the second inequality yields $4x - 4 < 2$, which simplifies to $4x < 6$ or $x < \frac{3}{2}$. Graphing both results shows that the intersection of $x \leq 3$ and $x < \frac{3}{2}$ is the interval where $x < \frac{3}{2}$. In interval notation, this overlapping solution is written as $(-\infty, \frac{3}{2})$.