To practice solving a compound inequality, solve $5(3x-1) \leq 10$ and $4(x+3) < 8$. Solving the first inequality gives $15x - 5 \leq 10$, which simplifies to $15x \leq 15$ or $x \leq 1$. Solving the second inequality yields $4x + 12 < 8$, which simplifies to $4x < -4$ or $x < -1$. Graphing both results shows that the intersection of $x \leq 1$ and $x < -1$ is the interval where $x < -1$. In interval notation, this overlapping solution is written as $(-\infty, -1)$.