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Try It 10.56: Evaluating log51\log_5 1 and log77\log_7 7

Evaluate each logarithmic expression using the basic properties of logarithms.

ⓐ To evaluate log51\log_5 1, apply the property loga1=0\log_a 1 = 0. Since 55 is a valid base (5>05 > 0 and 5eq15 eq 1), the expression evaluates directly to 00. Therefore, log51=0\log_5 1 = 0.

ⓑ To evaluate log77\log_7 7, apply the property logaa=1\log_a a = 1. Since the argument equals the base, the result is 11. Therefore, log77=1\log_7 7 = 1.

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Updated 2026-05-25

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