To further practice solving "and" compound inequalities, consider $3x - 4 < 5$ and $4x + 9 \geq 1$. For the first inequality, adding $4$ gives $3x < 9$, so $x < 3$. For the second, subtracting $9$ gives $4x \geq -8$, so $x \geq -2$. The numbers that make both inequalities true are those where the graphs of $x < 3$ and $x \geq -2$ overlap. This interval includes $-2$ but excludes $3$. Written in interval notation, the final solution is $[-2, 3)$.