Example

Example: Solving 4x35|4x - 3| \geq 5 and 3x42|3x - 4| \geq 2

To solve the absolute value inequalities 4x35|4x - 3| \geq 5 and 3x42|3x - 4| \geq 2, apply the standard procedure for 'greater than or equal to' inequalities by translating each into a compound inequality. For 4x35|4x - 3| \geq 5, the equivalent compound inequality is 4x354x - 3 \leq -5 or 4x354x - 3 \geq 5. Solving each part for xx yields x12x \leq -\frac{1}{2} or x2x \geq 2. In interval notation, this solution set is (,12][2,)(-\infty, -\frac{1}{2}] \cup [2, \infty). Similarly, for 3x42|3x - 4| \geq 2, the equivalent compound inequality is 3x423x - 4 \leq -2 or 3x423x - 4 \geq 2. Solving for xx gives x23x \leq \frac{2}{3} or x2x \geq 2, which is expressed in interval notation as (,23][2,)(-\infty, \frac{2}{3}] \cup [2, \infty).

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Updated 2026-06-27

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