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Analyze how correcting the standard deviation of Group 2 from 5 to 10 affects each component of the independent-samples -test formula's denominator and the final statistic, assuming all other values remain constant.
Case context: A research team runs an independent-samples -test to compare the effects of two study techniques on exam scores. Group 1 () has and . Group 2 () has and . Later, they realize the standard deviation of Group 2 was recorded incorrectly and is actually instead of 5.
Question: Analyze how correcting the standard deviation of Group 2 from 5 to 10 affects each component of the independent-samples -test formula's denominator and the final statistic, assuming all other values remain constant.
Sample answer: Increasing from 5 to 10 increases the variance () from 25 to 100. Consequently, the term increases from to . This increases the sum of the variances divided by their sample sizes inside the square root from to , which in turn increases the entire denominator (the square root of the sum) from to . Because the denominator increases while the numerator (the mean difference ) remains constant, the final calculated statistic decreases (from to ).
Key points:
- Identify that the variance (SD squared) of Group 2 increases from 25 to 100.
- Identify that the term SD2^2 / n2 increases from 1 to 4.
- Identify that the sum inside the square root in the denominator increases (from 5 to 8).
- Identify that the denominator (square root of the sum) increases.
- Explain that a larger denominator with a constant numerator leads to a smaller overall t statistic.
Rubric: Student must trace the change from standard deviation to variance, show how this increases the specific group's variance/n term, explain how this increases the overall denominator, and conclude that an increased denominator with a constant numerator results in a smaller final t statistic.
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Research Methods in Psychology - 4th American Edition @ KPU
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