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Evaluating 2x2xy+3y22x^2 - xy + 3y^2 when x=2x = -2 and y=3y = 3

To evaluate the two-variable algebraic expression 2x2xy+3y22x^2 - xy + 3y^2 for x=2x = -2 and y=3y = 3, substitute the assigned values into the expression using parentheses to ensure proper sign management: 2(2)2(2)(3)+3(3)22(-2)^2 - (-2)(3) + 3(3)^2. According to the order of operations, evaluate the exponents first to get (2)2=4(-2)^2 = 4 and (3)2=9(3)^2 = 9, resulting in 2(4)(2)(3)+3(9)2(4) - (-2)(3) + 3(9). Next, perform the multiplications to obtain 8(6)+278 - (-6) + 27. Converting the subtraction of a negative number into addition gives 8+6+278 + 6 + 27. Finally, add these numbers together to arrive at the final evaluated result of 4141.

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Updated 2026-04-27

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